17=4(v^2+1)

Solution for 17=4(v^2+1) equation:

Simplifying
17 = 4(v2 + 1)

Reorder the terms:
17 = 4(1 + v2)
17 = (1 * 4 + v2 * 4)
17 = (4 + 4v2)

Solving
17 = 4 + 4v2

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-4v2' to each side of the equation.
17 + -4v2 = 4 + 4v2 + -4v2

Combine like terms: 4v2 + -4v2 = 0
17 + -4v2 = 4 + 0
17 + -4v2 = 4

Add '-17' to each side of the equation.
17 + -17 + -4v2 = 4 + -17

Combine like terms: 17 + -17 = 0
0 + -4v2 = 4 + -17
-4v2 = 4 + -17

Combine like terms: 4 + -17 = -13
-4v2 = -13

Divide each side by '-4'.
v2 = 3.25

Simplifying
v2 = 3.25

Take the square root of each side:
v = {-1.802775638, 1.802775638}